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 Math problem
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Posted on 04-14-15 6:07 PM     Reply [Subscribe]
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Guys! try to solve this problem. Google later. Just for fun
Albert and Bernard just met Cheryl. “When’s your birthday?” Albert asked Cheryl.

Cheryl thought a second and said, “I’m not going to tell you, but I’ll give you some clues.” She wrote down a list of 10 dates:

May 15 — May 16 — May 19

June 17 — June 18

July 14 — July 16

August 14 — August 15 — August 17

“My birthday is one of these,” she said.

Then Cheryl whispered in Albert’s ear the month — and only the month — of her birthday. To Bernard, she whispered the day, and only the day.

“Can you figure it out now?” she asked Albert.

Albert: I don’t know when your birthday is, but I know Bernard doesn’t know, either.

Bernard: I didn’t know originally, but now I do.

Albert: Well, now I know, too!

When is Cheryl’s birthday?
 
Posted on 04-14-15 11:49 PM     [Snapshot: 104]     Reply [Subscribe]
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I came up with either may 19 or June 18 but neither of em is correct. I don't know why the answer is July 16
 
Posted on 04-15-15 2:34 AM     [Snapshot: 137]     Reply [Subscribe]
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Spoiler Alert (I didn't solve it)

















"Remember, Albert is told either May, June, July or August. Bernard is told either 14, 15, 16, 17, 18 or 19 Let’s go through it line by line. Albert: I don’t know when Cheryl’s birthday is, but I know that Bernard doesn’t know too. All Albert knows is the month, and every month has more than one possible date, so of course he doesn’t know when her birthday is. The first part of the sentence is redundant. The only way that Bernard could know the date with a single number, however, would be if Cheryl had told him 18 or 19, since of the ten date options only these numbers appear once, as May 19 and June 18. For Albert to know that Bernard does not know, Albert must therefore have been told July or August, since this rules out Bernard being told 18 or 19. Line 2) Bernard: At first I don’t know when Cheryl’s birthday is, but now I know. Bernard has deduced that Albert has either August or July. If he knows the full date, he must have been told 15, 16 or 17, since if he had been told 14 he would be none the wiser about whether the month was August or July. Each of 15, 16 and 17 only refers to one specific month, but 14 could be either month. Line 3) Albert: Then I also know when Cheryl’s birthday is. Albert has therefore deduced that the possible dates are July 16, Aug 15 and Aug 17. For him to now know, he must have been told July. Since if he had been told August, he would not know which date for certain is the birthday. The answer, therefore is July 16."
 
Posted on 04-15-15 3:43 AM     [Snapshot: 155]     Reply [Subscribe]
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Oh man baffled my head.. Still got questions
 
Posted on 04-15-15 9:13 AM     [Snapshot: 278]     Reply [Subscribe]
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I came up with the answer yesterday.
Here is my Explanation:
Answer is July 16
- 18 & 19 is out coz then Bernard would have known the bday as he knows the date and 18 & 19 occurs only once.
- May & June is out coz if its may or june ots possible for Bernard to know bday is 18 or 19. So the month has to be July or August
- Now Bernard knows the bday, means that it cannot be 14, so 14 is out.
- Now only 3 date is remaining. July 16, aug 15 and aug 17
- As there are 2 Aug, it cannot be august coz Albert would not have known bday. He knows means its July.
- As there is only one July its July 16

Enjoy !
 
Posted on 04-15-15 10:28 AM     [Snapshot: 348]     Reply [Subscribe]
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This was on news too.
Question was ? is it can be a math problem ?
 


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